orbital speed = 2x (pi) x orbital radius
time period
y = 2x (pi) x r
time period
y = 2x (pi) x r
T
calculate the speed of a stellite that is orbiting 200km above the earth's surface and completes one orbit in 1h 24 min. The radius of the earth is 6400 km
EQN V = 2(pi)r T
SUB V = 2x(pi)x(200+6400)
(60+24)x60
= 8.22 km/s
Planet | Distance from Sun (astronomical units (AU) | Time for orbit (years) | Speed (AU per year) |
Mercury | 0.4 | 0.2 | 12.57 |
Venus | 0.7 | 0.6 | 7.33 |
Earth | 1.0 | 1.0 | 6.28 |
Mars | 1.5 | 1.9 | 4.96 |
Jupiter | 5.0 | 12.0 | 2.62 |
Saturn | 9.5 | 30.0 | 1.99 |
Uranus | 19.0 | 84.0 | 1.42 |
Neptune | 30.0 | 165.0 | 1.14 |
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