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Monday, April 4, 2011

1.33 use the relationship between orbital speed, orbital radius and time period

orbital speed = 2x (pi) x orbital radius                                  
                          time period
   y
= 2x (pi) x          
            T

 
 
calculate the speed of a stellite that is orbiting 200km above the earth's surface and completes one orbit in 1h 24 min. The radius of the earth is 6400 km
EQN    V = 2(pi)r      
                       T
SUB   V = 2x(pi)x(200+6400)      
                     (60+24)x60

= 8.22 km/s
PlanetDistance from Sun (astronomical units (AU)Time for orbit (years)Speed (AU per year)
Mercury0.40.212.57
Venus0.70.67.33
Earth1.01.06.28
Mars1.51.94.96
Jupiter5.012.02.62
Saturn9.530.01.99
Uranus19.084.01.42
Neptune30.0165.01.14

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